Clarification on 2E.5

(Polar molecules, Non-polar molecules, etc.)

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ShravanPatel2B
Posts: 100
Joined: Fri Aug 30, 2019 12:18 am

Clarification on 2E.5

Postby ShravanPatel2B » Sun Nov 17, 2019 4:06 pm

On this problem I got that the OCLO bong angle would be 120 degrees but why is it less than 120 degrees?
Is this due to the lone pairs on the oxygens pulling away from the central atom resulting in a smaller angle?

Thanks!

Sydney Jacobs 1C
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Joined: Thu Jul 25, 2019 12:15 am
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Re: Clarification on 2E.5

Postby Sydney Jacobs 1C » Sun Nov 17, 2019 4:19 pm

In the Lewis Structure, the central atom is Cl, which has a lone pair. The VSEPR formula is therefore AX2E, giving the molecule an angular shape. In the trigonal planar shape, all angles would be 120 degrees. However, in the angular shape, the lone pair on the central atom (in this case Cl) repels the bonding pairs between O and Cl. This therefore compresses the angles to less than 120 degrees.


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