2E.19 b

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Clarice Chui 2C
Posts: 101
Joined: Fri Aug 30, 2019 12:16 am

2E.19 b

Postby Clarice Chui 2C » Sun Nov 17, 2019 4:49 pm

b) (CH3)2Be
I drew the Lewis structure no problem, but why is the shape tetrahedral?

Harry Zhang 1B
Posts: 101
Joined: Sat Sep 14, 2019 12:16 am

Re: 2E.19 b

Postby Harry Zhang 1B » Sun Nov 17, 2019 4:52 pm

It is tetrahedral about the carbon atom but it is linear about the Be atom.

eduardomorales5
Posts: 77
Joined: Fri Aug 30, 2019 12:15 am

Re: 2E.19 b

Postby eduardomorales5 » Sun Nov 17, 2019 4:56 pm

By drawing VSEPR structure, it takes the shape of a tetrahedral for both of the carbons. It would look like two tetrahedral bonded together by the carbon. So H3C-CH2BeH. The H3C would be a tetrahedral and so would the CH2BeH.


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