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2E.19 b

Posted: Sun Nov 17, 2019 4:49 pm
by Clarice Chui 2C
b) (CH3)2Be
I drew the Lewis structure no problem, but why is the shape tetrahedral?

Re: 2E.19 b

Posted: Sun Nov 17, 2019 4:52 pm
by Harry Zhang 1B
It is tetrahedral about the carbon atom but it is linear about the Be atom.

Re: 2E.19 b

Posted: Sun Nov 17, 2019 4:56 pm
by eduardomorales5
By drawing VSEPR structure, it takes the shape of a tetrahedral for both of the carbons. It would look like two tetrahedral bonded together by the carbon. So H3C-CH2BeH. The H3C would be a tetrahedral and so would the CH2BeH.