(Polar molecules, Non-polar molecules, etc.)

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Postby JamieVu_2C » Sun Nov 17, 2019 5:28 pm

For part b, the book solutions manual states that TeCl4 has a seesaw molecular shape, but its bond angles are 90 degrees and 120 degrees. If Te has a lone pair on an equatorial position in its seesaw structure, why do the bond angles equal 90 degrees and 120 degrees? Shouldn't they be slightly less than 90 degrees and 120 degrees because of the repulsion from the lone pair?

Nicholas Chin 1G
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Re: 2E.15B

Postby Nicholas Chin 1G » Sun Nov 17, 2019 5:30 pm

We know that the bond angles are going to be distorted to slightly less than 120 and 90 degrees, but since we can't actually know how much, we usually say that there the bond angles are 90 and 120. In my discussion session, my TA said there would then be a followup question that asks if there is angle distortion.

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