Influence of Lone Pair e- on Model

[DTingey_1C]

I know that Lavelle said that lone pair e- impact the shape of the molecule, but is the impact of a greater or lesser magnitude than if an atom were in the place of the lone pair? I hope this isn't too confusing.

[Mansi_1D]

Yes, if there is a lone pair, they push down on the atom because they have greater repulsion than bonding pairs, and thus greater impact.

[Edmund Zhi 2B]

Having a lone pair has a greater effect on repulsion because if you think about it, only one atom will be fighting for electrons, where as if there was a bond, two atoms would be exhibiting a nuclear force on the electrons. This means that the lone pair will be pulled closer to the nucleus, and the closer negative charges of the electrons will have greater magnitude of repulsion than if there were an atom in place.

[Rosa Munoz 2E]

Lone-Lone pair PR is greater than the rest.

[Bradley Whitworth 4B]

Greater impact, a lone pair would create more repulsion than just another atom.

[005206171]

Greater. A lone pair will increase e- repulsion, causing the bond angles to be slightly smaller than if there was an atom in place.