(Polar molecules, Non-polar molecules, etc.)

Moderators: Chem_Mod, Chem_Admin

Posts: 108
Joined: Thu Jul 25, 2019 12:16 am


Postby JamieVu_2C » Sun Nov 17, 2019 11:25 pm

For part A, if you weren't given the information that C5H5N, pyridine, has a similar structure to benzene, how would you know to draw it as a ring structure?

Posts: 164
Joined: Fri Aug 30, 2019 12:16 am

Re: 2E.27A

Postby sarahsalama2E » Sun Nov 17, 2019 11:30 pm

Typically when there are a lot of carbons in a molecule, it forms a carbon structure, like a benzene ring. But however, it can also form chains. I have noticed that typically when there are more than 4 carbons, a ring is formed. Also, pay attention to how the molecule is written out. The way that pyridine is written kind of lends itself to a ring like structure.

Return to “Determining Molecular Shape (VSEPR)”

Who is online

Users browsing this forum: No registered users and 1 guest