Shape
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 61
- Joined: Wed Sep 30, 2020 9:51 pm
-
- Posts: 106
- Joined: Wed Sep 30, 2020 9:54 pm
-
- Posts: 101
- Joined: Wed Sep 30, 2020 10:03 pm
- Been upvoted: 2 times
-
- Posts: 91
- Joined: Wed Sep 30, 2020 9:43 pm
- Been upvoted: 3 times
-
- Posts: 97
- Joined: Wed Sep 30, 2020 9:35 pm
Re: Shape
Should be linear, otherwise I believe you could not discern the answer with only that info.
-
- Posts: 82
- Joined: Wed Sep 30, 2020 9:35 pm
-
- Posts: 159
- Joined: Wed Sep 30, 2020 9:32 pm
- Been upvoted: 5 times
Re: Shape
It is linear because if there was one lone pair, and four bonding pairs, the lone pair would be in the equatorial plane so the more repulsive lone pair only reacts with 2 bonds at 90 degrees. Using the same logic, the next two lone pairs would also be removed from the equatorial plane, leaving two bonding pairs 180 degrees apart from each other, making the shape linear.
Hope this helps!
Hope this helps!
-
- Posts: 91
- Joined: Wed Sep 30, 2020 9:50 pm
- Been upvoted: 1 time
-
- Posts: 94
- Joined: Wed Sep 30, 2020 9:40 pm
-
- Posts: 94
- Joined: Wed Sep 30, 2020 9:37 pm
-
- Posts: 90
- Joined: Wed Sep 30, 2020 9:35 pm
Re: Shape
The result of two bonding pairs and a total of three lone pairs is a linear shape. I have found it useful to reference a VSEPR chart to familiarize myself with the specific geometries with their respective lone pair and domains of electron density.
Return to “Determining Molecular Shape (VSEPR)”
Who is online
Users browsing this forum: No registered users and 3 guests