Question three is telling me to to say which what the smallest angle would be
X-Y-X ( Y has 2 lone pairs on top and one lone pair on the bottom?
How does one determine the angle?
thank you.
sapling HW question three
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Re: sapling HW question three
I think what it's really asking is the smallest bond angle possible, and because this is a linear shape, it would be 180 degrees. These measurements were talked about in the lectures, so you don't have to necessarily do any calculations :)
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Re: sapling HW question three
magalysantos_1F wrote:I think what it's really asking is the smallest bond angle possible, and because this is a linear shape, it would be 180 degrees. These measurements were talked about in the lectures, so you don't have to necessarily do any calculations :)
thank you!
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Re: sapling HW question three
the smallest bond angle would be 109.5 because the molecule is AX2E2 (central atom, 2 outer atoms, 2 lone pairs) meaning the shape is angular/bent!
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Re: sapling HW question three
Well the molecule has five areas of electron density. The VSEPR formula is AX2E3, so you know that it began with a base geometry of trigonal bipyramidal. Once you remove 3 bonds for lone pairs, you are left with a linear shape and the bond angle would be 180 degrees. I usually like to work my way down from the base geometry, I hope that helps!
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Re: sapling HW question three
the molecule would have 5 regions of electron density so you would start with a trigonal bipyramidal shape (but that is not counting lone pairs). the VSEPR notation is AX2E3, and from the VSEPR chart you know that it's a linear shape so the bond angle is 180 degrees
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