(Polar molecules, Non-polar molecules, etc.)
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Hi, so I understand that lone pairs decrease bond angles, for example NH3 goes from 109.5 to 107, but someone explain why this happens? Does it have to due with the energy of the lone pairs being higher?
Hi! So lone pairs have the greatest repulsion and they occupy a larger volume so they will push the bonding pairs down and slightly distort the bond angles by forcing the bond pairs together slightly. I hope this helps!!
Since lone pairs have very high repulsion, they push bonding pairs away from themselves and closer to other bonding pairs, therefore decreased bond angles between them. Hope this helped :)
Lone pairs actually have the highest repulsion, meaning they push the bonds farther away compared to if they were not lone pairs. This causes the bond angles to decrease.
Lone pairs have a greater repulsion in comparison to boned pairs. These lone pairs therefore force the bonded pairs close to one another, as the lone pairs take up a greater space due to the repulsion.
Hi! Lone pairs occupy a larger volume, and the repulsion strength between a lone pair and a bonding pair is greater than that of a bonding pair and a bonding pair. Due to this, the lone pairs push down on the bonded pairs, distorting (decreasing) the bond angles. Hope this helps!
Think of it like lone pairs being stubby areas of high density while bonds are more narrow and long. the stubby one will push the narrow ones together slightly to make room for itself, therefore making the bond angles smaller.
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