Sapling #18

(Polar molecules, Non-polar molecules, etc.)

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Zach Richardson 2f
Posts: 68
Joined: Wed Sep 30, 2020 9:32 pm

Sapling #18

Postby Zach Richardson 2f » Sun Nov 29, 2020 11:36 pm

Can someone explain to me why an odd number of carbons will cause the end hydrogen atoms to be on perpendicular planes? I understand that it has something to do with the pi-bonds, but why exactly?

IreneSeo3F
Posts: 87
Joined: Wed Sep 30, 2020 9:31 pm

Re: Sapling #18

Postby IreneSeo3F » Sun Nov 29, 2020 11:54 pm

According to the solution, the pi bonds in C=C are perpendicular to one another in H2CCCH2 molecules, while pi bonds in terminal C=C bonds are parallel to one another in even number of C molecules. Thus, H atoms are coplanar when there are even number of C atoms.

Isaac Wen
Posts: 58
Joined: Wed Sep 30, 2020 9:35 pm
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Re: Sapling #18

Postby Isaac Wen » Thu Dec 03, 2020 11:10 pm

If the pi bonds between the first two central carbon atoms are connected by two p orbitals in the x orientation, the pi bonds between the second and third central carbon atoms have to be connected by two p orbitals in either the y or z orientation. That is what accounts for the perpendicular plane. Subsequently, the hydrogen atoms connected to the third (or odd #) carbon atom won't be in the same plane as the hydrogen atoms connected to the first carbon attom.


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