Textbook Problem 2E.21) d.

(Polar molecules, Non-polar molecules, etc.)

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ellenulitsky Dis 1I
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Textbook Problem 2E.21) d.

Postby ellenulitsky Dis 1I » Sun Dec 06, 2020 8:00 pm

N2H4 makes the trigonal pyramidal shape, which should have an angle of <109.5 degrees, however in the answer key, it says that the angle is 107 degrees. How should we know the exact degrees for this molecule? Thank you!

Nathan Tong 3G
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Re: Textbook Problem 2E.21) d.

Postby Nathan Tong 3G » Sun Dec 06, 2020 8:08 pm

I don't believe we've learned a way to calculate the angle of 107o, so simply knowing that the angles are <109.5 because of the lone pairs should be good enough.

Sonel Raj 3I
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Re: Textbook Problem 2E.21) d.

Postby Sonel Raj 3I » Sun Dec 06, 2020 8:14 pm

According to his lectures, I am pretty sure we won't need to know the exact bond angle, and, rather, we should just know what effect lone pairs have on bond angles and molecule shape. Knowing that the angles are less that 109.5 due to the lone pairs is enough, I am pretty sure!

Connie Liang 3L
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Re: Textbook Problem 2E.21) d.

Postby Connie Liang 3L » Sun Dec 06, 2020 8:58 pm

All we need to know is that it's less than 109.5! :)


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