A question from the final

[Nancy Yao]

Why is the shape of S_{2}O_{3}^{2-} tetrahedral? I drew a trigonal pyramidal shape and find that also works, which has a S-S bond in the center, and 2 oxygen bind to one S and 1 oxygen binds to the other S, but I googled after the exam and found that the shape is tetrahedral.

[Sid Panda 3A]

Why is the shape of S_{2}O_{3}^{2-} tetrahedral? I drew a trigonal pyramidal shape and find that also works, which has a S-S bond in the center, and 2 oxygen bind to one S and 1 oxygen binds to the other S, but I googled after the exam and found that the shape is tetrahedral.

I also drew a trigonal pyramidal shape as well. I think it might not be trig pyramidal because if you draw it in a trigonal pyramid shape, then you have 2 central atoms. But, I believe the tetrahedral shape only has one central atom which would fit better with naming shapes.

[Jiwon_Chae_3L]

I think that it's tetrahedral because its the most stable state for S2O3

[allyssa bradley 1H]

I looked it up after the test and I agree with tetrahedral!

[Fernanda Olvera 3D]

I also think it is tetrahedral!

[Nicole Bruno Dis 1B]

In this molecule, the central S atom is bonded to 1 S and 3 O with no lone pairs, so there are 4 regions of electron density which must be arranged tetrahedrally.