bond angle [ENDORSED]
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Re: bond angle
Tetrahedral bond angles are 109.5o, but keep in mind that if there are lone pairs that contribute to the tetrahedral outline (so that naming the shape would be trigonal pyramidal or bent) the bond angles will be less than 109.5.
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Re: bond angle
It would be 109.5 degrees. You also have to keep in mind that the bond angles can change if there are lone pairs.
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Re: bond angle
The bond angles would be 109.5 degrees. In an electron arrangement of tetrahedral but with one lone pair, the bond angles would be <109.5 degrees. With two lone pairs, it would be <<109.5 degrees.
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Re: bond angle
It's 109.5 degree, because the atoms/groups of atoms are arranged into a least repulsion form.
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Re: bond angle
For tetrahedrals, the bond angle would be 109.5 degrees. Methane is a common example of this where it has no lone pairs and four bonds, therefore it is a tetrahedron with 109.5 degrees for each bond between C and H.
Re: bond angle
As all of the atoms are arranged symmetrically around the central atom in a molecule with a tetrahedral shape, there will only be one bond angle as all the bonds are equal distance away from each other. For a tetrahedral molecule, the bond angle is around 109.5°.
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Re: bond angle
For tetrahedral bonds, it is 109.5. For when they have lone pairs, it is less than 109.5
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Re: bond angle
Hi!
The bond angles of a tetrahedral shape is 109.5o between the outer atoms because they are all equidistant from each other.
Hope this helps!
The bond angles of a tetrahedral shape is 109.5o between the outer atoms because they are all equidistant from each other.
Hope this helps!
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Re: bond angle
Hi, the bond angles of a tetrahedral shape is 109.5 degrees since there are four bonds and no lone pairs around the central atom in the molecule. Hope this helps!
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Re: bond angle
The bond angles of a tetrahedral-shaped molecule would be 109.5 degrees because that is the angle at which the four regions of electron density around the central atom are furthest from each other.
Re: bond angle
Bond angles of a tetrahedral shaped molecule is 109.5, however if there are lone pairs such as AX3E or AX2E2, then the bond angle is slightly less than 109.5. AX3E will have a bond angle of around 107 while AX2E2 will have a bond angle of about 104.5. Thus, it is important to recognize the presence of lone pairs in consideration of the molecular geometry.
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Re: bond angle
For a tetrahedral shape (and no lone pairs), the bond angle is 109.5 degrees. However, for molecules with 4 bonding regions, where some are lone pairs, the bond angle is less than 109.5 degrees.
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Re: bond angle
Since the tetrahedral shape includes 3 elements that surround a central atom, the bond angles of any given 3 elements (<ABC) will be 109.5 degrees.
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Re: bond angle
Hi! The bond angle for tetrahedral shape would be 109.5 degrees or less if there is repulsion caused by lone pairs.
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Re: bond angle
The tetrahedral bond angle is 109.5 degrees. Keep in mind that if you have lone pairs within that tetrahedral structure, then the bond angle should be <109.5
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Re: bond angle
Since the bonds are not limited to a 2D space, the best arrangement in a tetrahedral shape (in which the angles between bonds are maximized) is 109.5 degrees. I like to remember it as being less than 120 degrees since trigonal planar is exactly 120 and tetrahedral has an extra region of electron density.
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Re: bond angle
The bond angle for the tetrahedral shape is 109.5. If there are lone pairs it will be <109.5.
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Re: bond angle
The standard bond angle for a tetrahedral shape is 109.5 degrees. It is important to note that this can vary depending on the presence of lone pairs.
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Re: bond angle
Tetrahedral bond angles are all 109.5º. The only way to know this is just to memorize it, and know that if an atom is replaced with a lone pair and the shape is trigonal pyramidal, the bond angles are less than 109.5º.
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Re: bond angle
Hi! The bond angle for a tetrahedral is 109.5 degrees because there are 4 atoms that are equidistant from the central atom.
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