Why is (CH3)2Be is sp? [ENDORSED]
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Why is (CH3)2Be is sp?
Question: Can you please explain to me why (CH3)2Be has a hybridization of sp rather than sp3? Is it because Be has an empty p orbital and lone pairs do not effect it?
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Re: Why is (CH3)2Be is sp?
Answer: Be is in group 2 and forms two bonds, one to each CH3. Placing Be in the center forms a linear molecule with two single bonds.Therefore Be is sp hybridization.
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Re: Why is (CH3)2Be is sp?
The central atom is always the one with the lowest electronegativity. Be is lower than C so it is in between the two carbons
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Re: Why is (CH3)2Be is sp?
On number 4.19, it says that (CH3)2BE is tetrahedral - how is that right if it's VSEPR is sp?
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Re: Why is (CH3)2Be is sp? [ENDORSED]
Please read things carefully.
The solution manual says the shape is a tetrahedral about the carbon atoms.
However, as a whole, the molecule is linear. Meaning with respect to the central Be atom in (CH3)2Be.
The solution manual says the shape is a tetrahedral about the carbon atoms.
However, as a whole, the molecule is linear. Meaning with respect to the central Be atom in (CH3)2Be.
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Re: Why is (CH3)2Be is sp?
Chem_Mod wrote:Please read things carefully.
The solution manual says the shape is a tetrahedral about the carbon atoms.
However, as a whole, the molecule is linear. Meaning with respect to the central Be atom in (CH3)2Be.
So to better understand, if the question were to ask of the shape in respect to the carbon atoms then the shape would be tetrahedral and if in respect to Be then the shape would be linear? Since the question doesnt specify would you just assume Be and just specify in the answer what your bond angle is refering to ?
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Re: Why is (CH3)2Be is sp?
Your statement is correct. You can also ask for clarification if it appears on the exam
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