25.d


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Blake_Katsev_2E
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Joined: Wed Sep 21, 2016 2:57 pm

25.d

Postby Blake_Katsev_2E » Fri Oct 28, 2016 7:29 pm

Hello, why would this molecule in problem 25.d be polar?
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Xinyi_Yan_3L
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Joined: Wed Sep 21, 2016 2:56 pm

Re: 25.d

Postby Xinyi_Yan_3L » Sat Oct 29, 2016 10:01 am

After sulfur forms bonds with each of the fluorine, it still has a lone pair left. The side with the lone pair has a slightly negative charge, thee other side has a slightly positive charge. So SF4 is polar.
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Aleena_Sorf_2A
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Re: 25.d

Postby Aleena_Sorf_2A » Fri Nov 11, 2016 6:32 pm

The shape of SCl4 is trigonal bipyramid. Therefore, by drawing the VSEPR shape, we see that the dipole moments do not cancel out.
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