## Question 4.39 [ENDORSED]

$sp, sp^{2}, sp^{3}, dsp^{3}, d^{2}sp^{3}$

Moderators: Chem_Mod, Chem_Admin

Annah Khan 1B
Posts: 28
Joined: Fri Jul 22, 2016 3:00 am

### Question 4.39

"White phosphorus, P4, is so reactive that it bursts into flame in air. The four atoms in P4 form a tetrahedron in which each P atom is connected to three other p atoms. (a) Assign a hybridization scheme to the P4 molecule. (b) Is the P4 molecule polar or nonpolar?"

I successfully figured out part (a), but I'm having trouble with part (b). Would P4 be polar or nonpolar? And why? Thank you in advance!

Dabin Kang 1B
Posts: 22
Joined: Fri Jun 23, 2017 11:39 am
Been upvoted: 1 time

### Re: Question 4.39

P4 is nonpolar because the 4 P atoms are arranged about a center of symmetry and they have the same electronegativity.

Kevin Liu 3G
Posts: 28
Joined: Fri Sep 29, 2017 7:07 am

### Re: Question 4.39  [ENDORSED]

If it helps, think of each P atom, with equal electronegativity, tugging in 4 directions which equals out the net force thus making the molecule non polar. It's essentially an electron tug of war with everyone of the same strength.

Camille 4I
Posts: 57
Joined: Sat Aug 24, 2019 12:18 am

### Re: Question 4.39

How do the 4 phosphorus atoms form a tetrahedral? Wouldn't they form a trigonal planar shape?

brennayoung
Posts: 51
Joined: Fri Sep 20, 2019 12:17 am

### Re: Question 4.39

Why does P4 have the hybridization of sp3 and not sp2?

Return to “Hybridization”

### Who is online

Users browsing this forum: No registered users and 1 guest