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I have a question about how many pi bonds are formed in benzene. In class, professor Lavelle said that there are three pi bonds formed in benzene because there are three double bonds formed between C-C, but what about the unhybridized 2p electrons, don't they also form pi bonds with each other? Do we need to take account of that?
Last edited by Ya Gao on Fri Nov 17, 2017 2:20 pm, edited 1 time in total.
The Pi bonds are essentially formed when two unhbyridized p orbitals interact vertically and restrict movement around the double bond. The unbhtbridized p orbitals are responsible for the Pi bonds in benezene in this case.
In benzene, each carbon atom contributes one unhybridized 2p electron, giving us a total of 6 unhybridized 2p electrons. These 2p electrons bond together to form pi bonds; thus (6 2p electrons)/(2 electrons per bond) = 3 pi bonds. These 3 pi bonds are the double bonds involved in benzene's structure.
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