Question 2.43


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Lauren Huang 1H
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Joined: Fri Sep 28, 2018 12:16 am

Question 2.43

Postby Lauren Huang 1H » Tue Oct 30, 2018 10:41 pm

When writing out the electron configuration for silver and antimony, why is 4d^10 before 5s when 4d^10 is after 5s in the periodic table?

Heesu_Kim_1F
Posts: 60
Joined: Fri Sep 28, 2018 12:18 am

Re: Question 2.43

Postby Heesu_Kim_1F » Tue Oct 30, 2018 10:45 pm

Professor Lavelle said in class that we can write it in both ways. I think the solution manual writes out from the lowest quantum number to the highest quantum number. He also mentioned that if he prefers a certain way, then he will make sure to let us know. Hope this helps!

mayra martinez 1D
Posts: 32
Joined: Fri Sep 28, 2018 12:17 am

Re: Question 2.43

Postby mayra martinez 1D » Sun Nov 04, 2018 3:05 pm

The only reason we write it that way is that you want to go from the lowest quantum number which is 4d^10 to the highest quantum number which is 5s.

Isabelle_Maletz_3E
Posts: 27
Joined: Fri Apr 06, 2018 11:03 am

Re: Question 2.43

Postby Isabelle_Maletz_3E » Sun Nov 11, 2018 8:20 pm

It doesn't matter too much but the main reason is basically to keep the electron configuration in numerical order so 4d would come before 5s.

Atul Saha 3D
Posts: 30
Joined: Fri Sep 28, 2018 12:25 am

Re: Question 2.43

Postby Atul Saha 3D » Sun Nov 11, 2018 8:26 pm

Technically, when the 4d orbital is occupied, it exists at a lower energy state than 5s orbital. However, the 5s orbital is technically filled out before the 4d orbital.

Much Joy,
Atul Saha


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