## Hybridization

$sp, sp^{2}, sp^{3}, dsp^{3}, d^{2}sp^{3}$

Hanniel U 2B
Posts: 76
Joined: Fri Sep 28, 2018 12:16 am

### Hybridization

During lecture today, C2H4 had a sp^2 hybridization. But when it was expanded, it was 2sp^2 and 2p. I am confused about that.

Jonas Talandis
Posts: 60
Joined: Fri Sep 28, 2018 12:16 am

### Re: Hybridization

Since each C atom only has 3 regions of electron density, and we know that the number of these regions needs to be equal to the number of hybridized orbitals, the resulting hybrid orbitals will be 3 orbitals at the sp2 level. However, since there is one p orbital unaccounted for (there are 3 p orbitals), there is one regular, unhybridized p orbital left over at the 2p energy level. This one will be at 90 degrees, resulting in the side-by-side pi bond mentioned in lecture.