Hybridization 4.75


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Semi Yoon
Posts: 60
Joined: Fri Sep 28, 2018 12:27 am

Hybridization 4.75

Postby Semi Yoon » Sat Nov 24, 2018 7:20 pm

If an organic compound distilled from wood was found to have a molar mass of 32.04 g·mol^-1 and the following composition by mass: 37.5% C, 12.6% H, and 49.9% O. What are the bond angles about the carbon and oxygen atoms? What is the hybridization of the carbon and oxygen atoms? Is the molecule polar or not?

Joon Chang 2F
Posts: 59
Joined: Fri Sep 28, 2018 12:25 am

Re: Hybridization 4.75

Postby Joon Chang 2F » Sat Nov 24, 2018 8:35 pm

The compound is CH4O. The bond angles about the carbon and oxygen are 109.5 degrees because the carbon, 3 hydrogens, and oxygen form a tetrahedral shape with carbon in the center. The hybridization of the carbon and oxygen atoms are both sp3 because they each have 4 regions of electron density. The molecule is polar.

Kevin Tang 4L
Posts: 83
Joined: Fri Sep 28, 2018 12:28 am

Re: Hybridization 4.75

Postby Kevin Tang 4L » Sun Nov 25, 2018 12:19 am

First, we need to change the information given about the composition of this molecule into the molecular formula:

37.5% C * 32.04g/mol = 12.0g C / 12.0107g/mol = 1mol C
12.6% H * 32.04g/mol = 4.03g H / 1.007g/mol = 4mol H
49.9% O * 32.04g/mol = 16.0g O / 15.9994g/mol = 1mol O

CH4O, which can also be written as H3COH* (correct me if im wrong as i'm not 100% about H3COH)

Carbon will be sp3 hybridized because it has four electron domains and Oxygen will be sp3 hybridized because it also has 4 electron domains from the two sigma bonds and two lone pairs. This gives the shape of tetrahedral for the carbon, which gives an angle of 109.5 and for the oxygen, it will be slightly less than 109.5 degrees because of the lone pairs.

This is a polar molecule.


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