## Figuring out the hybirdization

$sp, sp^{2}, sp^{3}, dsp^{3}, d^{2}sp^{3}$

Ariana Morales
Posts: 29
Joined: Fri Sep 28, 2018 12:15 am

### Figuring out the hybirdization

My question is specific to the numbers on top of s, p, and d. Why is the maximum electrons on p 3 and not 6 when the octet is full by 6 electrons?

Rami_Z_AbuQubo_2K
Posts: 89
Joined: Thu Jun 07, 2018 3:00 am

### Re: Figuring out the hybirdization

Do you remember the box method that was taught in high school? Each box with one electron inside of it opens itself up to bonding. When looking at the boxes, the s has only one box which allows two total electrons, the p has 3 boxes which allows 6 total electrons, the d has 5 boxes which allow for 10 electrons, and the f has 7 boxes which allow for 14 total electrons. The numbers on the top signify when an electron occupies that box, which then makes it capable for bonding. That number on top signifies how many single electrons there are in the p orbital which allow for bonding to a different element.

Ronak Singh
Posts: 31
Joined: Fri Sep 28, 2018 12:16 am

### Re: Figuring out the hybirdization

The 3 in sp3 means that out of the 4 total hybrid orbitals, 3 come from p orbitals.