2F.15 question 7th edition
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2F.15 question 7th edition
So why does the bond angle increase as the s character of a hybrid orbital increase?
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Re: 2F.15 question 7th edition
By the s-character increasing, it means the percentage of s in the hybrid. So sp^3, s is 25% or 1/4, whereas sp^2 is 33.3% or 1/3, and sp has s at 50%. These correlate to different angles as well, so that when there is sp^3, s is at 25% or a 109.5 degree angle. And sp^2 has 33% indicating a 120 degree angle. Therefore, as the s character increases, the bond angle size increases as well.
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