## 2F.15 question 7th edition

$sp, sp^{2}, sp^{3}, dsp^{3}, d^{2}sp^{3}$

Henri_de_Guzman_3L
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Joined: Fri Sep 28, 2018 12:25 am

### 2F.15 question 7th edition

So why does the bond angle increase as the s character of a hybrid orbital increase?

Henry Krasner 1C
Posts: 64
Joined: Fri Sep 28, 2018 12:15 am

### Re: 2F.15 question 7th edition

By the s-character increasing, it means the percentage of s in the hybrid. So sp^3, s is 25% or 1/4, whereas sp^2 is 33.3% or 1/3, and sp has s at 50%. These correlate to different angles as well, so that when there is sp^3, s is at 25% or a 109.5 degree angle. And sp^2 has 33% indicating a 120 degree angle. Therefore, as the s character increases, the bond angle size increases as well.

Henri_de_Guzman_3L
Posts: 88
Joined: Fri Sep 28, 2018 12:25 am

### Re: 2F.15 question 7th edition

That makes perfect sense thank you!

Henri_de_Guzman_3L
Posts: 88
Joined: Fri Sep 28, 2018 12:25 am

### Re: 2F.15 question 7th edition

That makes perfect sense thank you!

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