## Hybridization of pi bonds

$sp, sp^{2}, sp^{3}, dsp^{3}, d^{2}sp^{3}$

104904344
Posts: 27
Joined: Fri Sep 28, 2018 12:27 am

### Hybridization of pi bonds

Can someone explain how to find the hybridization of pi bonds? I understand how to find the hybridization of sigma bonds but am confused about finding the hybridization of pi bonds.

Karina Jiayu Xu 4E
Posts: 58
Joined: Fri Sep 28, 2018 12:29 am

### Re: Hybridization of pi bonds

Hybridized orbitals only occur for sigma bonds. Pi bonds take place in the leftover P orbitals.

Tessa Lawler 1A
Posts: 57
Joined: Fri Sep 28, 2018 12:18 am

### Re: Hybridization of pi bonds

You don't have to worry about finding the hybridization of specific types ("pi" or "sigma") of bonds. If an atom shares a triple bond with another atom, that atom has a sigma bond and two pi bonds. But it would still only get 1 level of hybridization (in this case, "s") from that bond, just like a separate atom that is single bound to another atom.

Alana Sur 3B
Posts: 61
Joined: Fri Sep 28, 2018 12:25 am

### Re: Hybridization of pi bonds

I found it easier to calculate hybridization by ignoring the same number of p orbitals as there are pi bonds in a molecule and then determining the hybridization with the remaining orbitals. For example, in HCN, C has one sigma bond with H and one with N, along with two pi bonds. Since there are two pi bonds, we know that 2 p orbitals remain untouched. The remaining orbitals (2s and one 2p) determine the hybridization of C - sp.