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You don't have to worry about finding the hybridization of specific types ("pi" or "sigma") of bonds. If an atom shares a triple bond with another atom, that atom has a sigma bond and two pi bonds. But it would still only get 1 level of hybridization (in this case, "s") from that bond, just like a separate atom that is single bound to another atom.
I found it easier to calculate hybridization by ignoring the same number of p orbitals as there are pi bonds in a molecule and then determining the hybridization with the remaining orbitals. For example, in HCN, C has one sigma bond with H and one with N, along with two pi bonds. Since there are two pi bonds, we know that 2 p orbitals remain untouched. The remaining orbitals (2s and one 2p) determine the hybridization of C - sp.
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