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Labeling hybridization in Test 3

Posted: Thu Dec 06, 2018 10:48 pm
by Rian Montagh 2K
For test 3 number 3c., I was asked to write the hybridization a nitrogen atom that was bonded to a carbon and two hydrogens, and had a lone pair. I thought that it would have a tetrahedral formation with the four e- densities, so I labeled it sp3 and it was wrong. What's the correct hybridization and why?

Re: Labeling hybridization in Test 3

Posted: Thu Dec 06, 2018 11:20 pm
by Henry Krasner 1C
Because of the 3 bonds and one lone pair, although the geometry is tetrahedral, the actual shape would be trigonal pyramidal, because of the lone pair. This would result in angles slightly less than 109.5 degrees.

Re: Labeling hybridization in Test 3

Posted: Fri Dec 07, 2018 10:39 pm
by Alana Sur 3B
Your hybridization was correct - 4 regions of electron density should be an sp3 hybridization