## 2.45 Hybridization

$sp, sp^{2}, sp^{3}, dsp^{3}, d^{2}sp^{3}$

ZainAlrawi_1J
Posts: 71
Joined: Sat Aug 24, 2019 12:16 am

### 2.45 Hybridization

Can someone explain how the hybridization of the lone pairs in part b of this question are derived? I have never seen a question like this before and I'm not even sure that we have went over it.

nicolely2F
Posts: 149
Joined: Sat Sep 14, 2019 12:17 am

### Re: 2.45 Hybridization

It follows the same logic as the bonds. The oxygen has a hybridization of sp2 (two being lone pairs) because it is connected to three areas of electron density; each lone pair will have that hybridization because they are electrons in hybridized orbitals, same as if they were bonded

DTingey_1C
Posts: 55
Joined: Fri Aug 30, 2019 12:16 am

### Re: 2.45 Hybridization

If it makes it easier to understand, think of the hybridization as something akin to the shape of the molecule. sp3 means there are 4 regions of e- density, meaning the shape can be AX4, AX3E, AX2E2, ect. This means that you can almost name a molecule as a tetrahedral by knowing that its hybridization is sp3, assuming there are no lone pairs.

Sears 4A
Posts: 36
Joined: Tue Feb 05, 2019 12:15 am

### Re: 2.45 Hybridization

however many regions of electron density an atom has, it will have exactly that many hybrid orbitals, even if they are lone pairs