## Sapling#11

$sp, sp^{2}, sp^{3}, dsp^{3}, d^{2}sp^{3}$

Shreya Patel- 2D
Posts: 96
Joined: Wed Sep 30, 2020 10:01 pm

### Sapling#11

Hi everyone! Why is the hybridization of the molecule below sp3? I am really confused with hybridization and lewis structure. Thank you!
Attachments

Ivan Chen 2H
Posts: 103
Joined: Wed Sep 30, 2020 9:48 pm

### Re: Sapling#11

It has 3 bonded atoms and one lone pair, so 4 hybrid orbitals are needed.

Ryan Laureano 3I
Posts: 97
Joined: Wed Sep 30, 2020 10:09 pm
Been upvoted: 1 time

### Re: Sapling#11

There are four orbitals needed to be filled. SP3 is the hybridization notation that fits this.

Lisa Wang 3B
Posts: 104
Joined: Wed Sep 30, 2020 9:51 pm

### Re: Sapling#11

Hi!
sp^3 would mean that s (1 orbital) and p^3 (3 orbitals) which corresponds to the 3 bonded pairs + 1 lone pair.

Jalyn 3G
Posts: 92
Joined: Wed Sep 30, 2020 9:59 pm

### Re: Sapling#11

Hello! Four hybrid orbitals are needed since there are 3 bonded pairs and 1 lone pair, which is given by sp^3. There is one orbital for s and 3 orbitals for p^3.

Bailey Giovanoli 1L
Posts: 112
Joined: Wed Sep 30, 2020 9:50 pm

### Re: Sapling#11

For some reason, this did not click in my head when Dr. Lavelle went over it in the lecture. However, this makes complete sense now. You guys are life savers!!

joshtully
Posts: 92
Joined: Wed Sep 30, 2020 9:36 pm

### Re: Sapling#11

It is because there are 4 orbitals (1 s and 3 p).