Unhybridized orbitals

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Marylyn Makar 1B
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Unhybridized orbitals

Postby Marylyn Makar 1B » Fri Dec 04, 2020 11:16 pm

Hi! How do you know when you have an unhybridized orbital and how do you know how many unhybridized orbitals to have? For example, how do you know that CO2 has 2 unhybridized 2p orbitals?

Khoa Vu 3l
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Joined: Wed Sep 30, 2020 9:59 pm

Re: Unhybridized orbitals

Postby Khoa Vu 3l » Fri Dec 04, 2020 11:57 pm

In looking at the lewis structure for CO2, you see that C has two regions of electron density and, therefore, has the hybridized orbital of sp, making one sigma sp bond with each oxygen. You know that there are two more unhybridized p orbitals because there are three total p orbitals for any energy level and one has already been hybridized. In general, you can tell how many remaining unhybridized orbitals there are based on the total number of orbitals in that subshell minus the number of orbitals in the same subshell that has already been hybridized. Oxygen, on the other hand, has three regions of electron density and has a hybridized orbital of sp2, leaving one unhybridized p orbital. This leaves the carbon two unhybridized p orbitals to make a pi p bond between each oxygen and their one remaining unhybridized p orbital.

Lauren Sarigumba 1K
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Joined: Wed Sep 30, 2020 9:41 pm

Re: Unhybridized orbitals

Postby Lauren Sarigumba 1K » Sat Dec 05, 2020 12:13 am

In the a table in the textbook, it says that a molecule with an electron arrangement that is linear, the hybridization of the central atom is sp. If it is trigonal planar, it is sp^2. If the electron arrangement is tetrahedral, it is sp^3. If the electron arrangement is trigonal bipyramidal, it is sp^3d. And if it is octahedral, it is sp^3d^2. The overarching rule is that N atomic orbitals always produce N hybrid orbitals.

Gian Boco 2G
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Joined: Wed Sep 30, 2020 9:36 pm

Re: Unhybridized orbitals

Postby Gian Boco 2G » Sun Dec 06, 2020 10:26 pm

Carbon has 4 valence electrons that can form bonds. In CO2, there are 2 regions of electron density in which the sp hybrid orbitals participate. There are still two more electrons, therefore there are two non hybridized orbitals.

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