what is the hybridization of N in NH3?
I didn't understand How professor got SP3 can someone clarify the steps? thank you
hybridization
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Re: hybridization
NH3 looks like a central nitrogen atom with three bonds connecting it to the hydrogen atoms and one lone pair. That means NH3 has four electron densities: 3 bonding pairs + 1 lone pair. When an atom has four electron densities, it uses sp3 hybridization, where the s and the three p orbitals allow it to form four electron densities.
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Re: hybridization
Nitrogen in NH3 has four regions of electron density. Three of them are single bonds with hydrogen and one is a lone pair. You can tell this based on the lewis structure he drew. Therefore, there should be four hybrid orbitals. To get four hybrid orbitals, you need one s orbital and three p orbitals. This means that NH3 is sp^3 hybridized.
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Re: hybridization
The number of regions of electron density = the number of hyrbridized orbitals. NH3 has 4 regions of electron density and sp3 is the hybridization with 4 hybrid orbitals.
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Re: hybridization
When we draw the lewis structure of NH3, we get 3 N-H bonds with one lone pair on the N. Which means that N has 4 regions of electron density and since hybridization depends on the # of electron density regions, we also need 4 hybridized orbital which correlates to a sp3 hybridization.
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Re: hybridization
It would be sp3 because there are 4 regions of electron density around the N (3 bonds with hydrogens and one lone pair)
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Re: hybridization
By looking at the lewis structure you can see that NH3 has four regions of electron density. Each bond counts as one region so thus we have three regions plus one one pair on the nitrogen that also counts as a lone pair. Since we have four regions of electron density we know that is has a hybridization of NH3 is sp3
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Re: hybridization
There are four regions of electron density around the N (one lone pair and 3 bonds). Therefore this means that it is sp3 hybridized.
Re: hybridization
so if you draw out the lewis structure you would see that N is in the middle and there are 3 hydrogens attached to N, as well as 1 lone pair. That means there are a total of 4 things surrounding N which explain the sp3 hybridization.... (s1p3 adds up to 4)
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Re: hybridization
look at the amount of electron densities so in this case, NH3 has 4, 3 ligands, and 1 lone pair. The number of electrons in sp^3 adds up to 4 (1 +3)
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Re: hybridization
In NH3, the molecule has three bonds and a lone pair of electrons, which adds up to four regions of electron density! When there are four regions of electron density, the sp3 hybridization is used!
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