## Final 2010 Q3A

$sp, sp^{2}, sp^{3}, dsp^{3}, d^{2}sp^{3}$

Maricruz Diagut 3J
Posts: 12
Joined: Fri Sep 25, 2015 3:00 am

### Final 2010 Q3A

Using the electron configuration identify the $M^{2+}$ cation.
(b)$[Ar] 3d^{4}$

I tried doing this problem by subtracting 2 electrons from the d orbital and adding them to the total electrons of Ar, but this didn't give me the right answer. I'm not sure how I can find the $M^{2+}$ cation?

Kim Vu 2G
Posts: 29
Joined: Fri Sep 25, 2015 3:00 am

### Re: Final 2010 Q3A

if you add up all the electrons from argon plus 4 from the 3d, you should have 22 electrons leaving you at Titanium. With a metal with a cation of 2+ that means that 2 electrons have previously been subtracted away from it leaving it with titanium with 2 less electrons. So to find the original state of the metal, add the 2 electrons and you should have Chromium.