Final 2010 Q3A


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Maricruz Diagut 3J
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Joined: Fri Sep 25, 2015 3:00 am

Final 2010 Q3A

Postby Maricruz Diagut 3J » Sat Dec 05, 2015 3:26 am

Using the electron configuration identify the cation.
(b)

I tried doing this problem by subtracting 2 electrons from the d orbital and adding them to the total electrons of Ar, but this didn't give me the right answer. I'm not sure how I can find the cation?

Kim Vu 2G
Posts: 29
Joined: Fri Sep 25, 2015 3:00 am

Re: Final 2010 Q3A

Postby Kim Vu 2G » Sat Dec 05, 2015 8:14 am

if you add up all the electrons from argon plus 4 from the 3d, you should have 22 electrons leaving you at Titanium. With a metal with a cation of 2+ that means that 2 electrons have previously been subtracted away from it leaving it with titanium with 2 less electrons. So to find the original state of the metal, add the 2 electrons and you should have Chromium.


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