#5 on the first quiz 2 preparation

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Leslie Romo 1C
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Joined: Fri Sep 25, 2015 3:00 am

#5 on the first quiz 2 preparation

Postby Leslie Romo 1C » Fri Oct 23, 2015 10:56 pm

The question is:
"Which of the following is the correct order of increasing stability?"


What does it mean by increasing stability and how do we find this???

Chem_Mod
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Re: #5 on the first quiz 2 preparation

Postby Chem_Mod » Fri Oct 23, 2015 11:24 pm

Could you please post what they are referring to? I don't have that book so I am a little lost.

Leslie Romo 1C
Posts: 21
Joined: Fri Sep 25, 2015 3:00 am

Re: #5 on the first quiz 2 preparation

Postby Leslie Romo 1C » Sat Oct 24, 2015 12:28 pm

The entire question is :

Which of the following is the correct order of increasing stability?

A) O2- > N2 > N2+ > C2
B) N2+ > N2 > O2- >C2
C) N2 > N2+ > C2 > O2-
D) N2 > N2+> O2- > C2



O2-: 13e- BO: 1.5
N2: 10 e- BO: 3
N2+: 9e- BO: 2.5
C2: 8e- BO: 2

Jacqueline Lee
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Joined: Fri Sep 25, 2015 3:00 am

Re: #5 on the first quiz 2 preparation

Postby Jacqueline Lee » Sat Oct 24, 2015 1:27 pm

We can describe stability of a molecule with bond order. Bond order can be found by
(# of electron in bonding molecular orbital - # of electron in anti-bonding molecular orbitals) divided by two. Anything above 0 means it would be stable, but the bigger the number you get for bond order would mean the molecule is more stable.

So given:
O2-: 13e- BO: 1.5
N2: 10 e- BO: 3
N2+: 9e- BO: 2.5
C2: 8e- BO: 2
from least to greatest order of stability would be : O2-, C2, N2+, N2
Or in other words,
N2 > N2+ > C2 > O2- which is option C.


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