Test 4
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Nickolas Manipud 1C
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Rachel Formaker 1E
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Re: Test 4
Diaquadifluoromercury(III)
Last edited by Rachel Formaker 1E on Sat Dec 09, 2017 8:16 pm, edited 1 time in total.
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Yuting Zhu 3D
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Re: Test 4
I was also wondering about how to determine the number after the name?
Last edited by Yuting Zhu 3D on Sat Dec 09, 2017 8:13 pm, edited 1 time in total.
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Nickolas Manipud 1C
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Re: Test 4
Rachel Formaker 1C wrote:Diaquadifluoromercury(I)
Wouldn't mercury have a charge of 3+ and not 1+?
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Vincent Kim 2I
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Re: Test 4
Yes, the oxidation number of Hg would be (III) instead of (I), as the two Fluoride ions make the overall charge -2, which requires a +3 oxidation state from the Hg to make the compound +1.
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