Ch. 17 #29, 6th edition
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Kristen Kim 2K
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Re: Ch. 17 #29, 6th edition
The Roman numeral in the parentheses is the oxidation number of the transition metal. The sum of all charges inside the brackets must add up to the charge on the overall coordination compound. For this specific problem, you are trying to find out the oxidation number of the transition metal.
To find the oxidation state of part a, as an example, you can set up an algebraic equation to solve for the oxidation number of Fe. We know that CN has a charge of -1.
Fe + 6(-1) = -4
Fe - 6 = -4
Fe = +2
To find the oxidation state of part a, as an example, you can set up an algebraic equation to solve for the oxidation number of Fe. We know that CN has a charge of -1.
Fe + 6(-1) = -4
Fe - 6 = -4
Fe = +2
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