9c.1 7th Edition
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9c.1 7th Edition
Hello! On part c0 of this question (pg 731), the answer is aquapentacyanocobaltate(III) ion. Is it written "cobaltate" and not simply "cobalt" because of the negative charge of the compound? If so, I assume that's why a) is also hexacyanoferrate(II) ion. How would you name that compound if the overall charge were positive? How would "ferrate" change in this case?
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Re: 9c.1 7th Edition
Yes, the -ate ending is indicating the negative charge and the ferrum comes from the Latin stem. In the book it states that if the metal originates form a latin name, then the latin stem will be used for negative charges only though!! If the overall charge was positive you would not use the latin stem or ending -ate so not ferrate, you would just say iron.
So to sum up, negative overall charges add an -ate ending as well as the latin stem if there is a latin stem to the element, NO latin stems for overall positive charges, just the regular element name.
So to sum up, negative overall charges add an -ate ending as well as the latin stem if there is a latin stem to the element, NO latin stems for overall positive charges, just the regular element name.
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Re: 9c.1 7th Edition
I was just about to ask why in parts b and d, the cobalt was simply stated as cobalt and not cobaltate in part c. Now I know that’s it’s because we only use the ate ending if the ion is negative. Thanks!
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