## Textbook Question 9C.1

Anne Kim 3F
Posts: 34
Joined: Fri Sep 28, 2018 12:25 am

### Textbook Question 9C.1

a) says [Fe(CN)6]^4-

however the answer is tetracholoroferrate (II)

why is iron called ferrate and why is the charge (II) and not (IV)

Lauren Ho 2E
Posts: 70
Joined: Tue Oct 09, 2018 12:16 am

### Re: Textbook Question 9C.1

Anne Kim 3F wrote:a) says [Fe(CN)6]^4-

however the answer is tetracholoroferrate (II)

why is iron called ferrate and why is the charge (II) and not (IV)

Each CN contributes to a -1 charge, meaning (CN)6 has a total charge of -6.

If [Fe(CN)6]^4- has a net charge of -4 and (CN)6 contributes to -6 of that charge, Fe must have a charge that, when added to -6, leads to -4. Therefore, it has a charge of +2.

Anne Kim 3F
Posts: 34
Joined: Fri Sep 28, 2018 12:25 am

### Re: Textbook Question 9C.1

laurenho-4c wrote:
Anne Kim 3F wrote:a) says [Fe(CN)6]^4-

however the answer is tetracholoroferrate (II)

why is iron called ferrate and why is the charge (II) and not (IV)

Each CN contributes to a -1 charge, meaning (CN)6 has a total charge of -6.

If [Fe(CN)6]^4- has a net charge of -4 and (CN)6 contributes to -6 of that charge, Fe must have a charge that, when added to -6, leads to -4. Therefore, it has a charge of +2.

Got it! Thanks!