ch 16 #29 part b

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Soraya Sadeghi 1B
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Joined: Fri Sep 26, 2014 2:02 pm

ch 16 #29 part b

Postby Soraya Sadeghi 1B » Sat Nov 29, 2014 3:54 pm

For part b, the question asks to write the formula for pentaaminesulfatocoobalt(III) chloride. Why is the answer
[Co(NH3)5 (SO4)] Cl instead of [Co(NH3)5 (SO4)] Cl3? I thought that there should be three Cl to cancel the charge of +3 on the Cobalt.

Astred 1D
Posts: 15
Joined: Fri Sep 26, 2014 2:02 pm

Re: ch 16 #29 part b

Postby Astred 1D » Sat Nov 29, 2014 4:01 pm

Hi,

So in this problem you have to look at the oxidation states (oxidation numbers). Sulfate has a -2 charge and you know Cobalt has a +3 charge if you add those oxidation states you have +1 as the total charge of the compound. Chlorine, the anion, has a -1 charge, thus the charges of both the cation ( the complex) and the anion cancel.


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