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### Oxidation

Posted: Sun Nov 24, 2019 8:46 pm
What's an oxidation number

### Re: Oxidation

Posted: Sun Nov 24, 2019 8:52 pm
Also can anyone explain what oxidation is? And what Dr. Lavelle meant by oxidation states? I don't remember him explaining the concept in class.

### Re: Oxidation

Posted: Sun Nov 24, 2019 8:53 pm
The oxidation number represents the number of electrons gained or lost by an element. For example, the oxidation number of oxygen in a compound is usually -2 because oxygen typically gains two electrons in a chemical reaction. However, the oxidation number of a neutral element is always zero (example O2).

### Re: Oxidation

Posted: Sun Nov 24, 2019 8:56 pm
The oxidation number/state is the charge that cation/anion has. For example, chlorine's oxidation state would be -1 (chloride).

### Re: Oxidation

Posted: Sun Nov 24, 2019 8:56 pm
An oxidation number represents the number of electrons lost or gained by an electron in a redox reaction.

### Re: Oxidation

Posted: Sun Nov 24, 2019 8:57 pm
The oxidation number, in reference to coordination compounds and complexes, is the number of electrons gained or lost (like charge) on the metal. For example, in the ion [Cr (Cl)2 (NH3)4]+, the oxidation number is III, giving the name tetraamminedichloridochromium (III). This is because the ion overall has a +1 charge, Cl- has a negative 1 charge, and ammonium has a neutral charge.

### Re: Oxidation

Posted: Sun Nov 24, 2019 9:03 pm
The oxidation number refers to the overall charge the molecule has

### Re: Oxidation

Posted: Wed Nov 27, 2019 1:13 pm
To add on, if the problem asks for the oxidation number of the metal, use:
(# of metal ion)*(oxidation number) + $\sum$(# if each ligand)*(charge of each ligand) = charge of ion

The charge of the ion should be given, allowing you to isolate and solve for the oxidation number of the metal.

### Re: Oxidation

Posted: Thu Nov 28, 2019 1:48 am
The oxidation number is the charge the atom would have if the compound was composed of ions. It is the number of electrons gained or loss to form a bond.

### Re: Oxidation

Posted: Thu Nov 28, 2019 3:29 pm
An oxidation number is the number of electrons lost or gained when making a chemical bond. If it is a negative number, the atom will gain electrons. If it is a positive number, the atom will lose electrons.

### Re: Oxidation

Posted: Thu Nov 28, 2019 4:26 pm
Kennedi3K wrote:Also can anyone explain what oxidation is? And what Dr. Lavelle meant by oxidation states? I don't remember him explaining the concept in class.

Hi Kennedi,

I agree with the other commenters about oxidation states and numbers. To answer your first questions, an oxidation reaction represents the loss of electrons. It contrasts with a reduction reaction, where electrons are gained. I hope this helps! Have a great day :D

-Rebecca

### Re: Oxidation

Posted: Fri Nov 29, 2019 2:24 am
Oxidation numbers indicate the number of electrons gained or lost by an atom in a molecule

### Re: Oxidation

Posted: Fri Nov 29, 2019 4:19 pm
is the oxidation number for the molecules always the same?

### Re: Oxidation

Posted: Sun Dec 01, 2019 11:33 pm
An oxidation number is a number associated with the charge that an atom would have if the compound was composed of ions.

### Re: Oxidation

Posted: Sun Dec 01, 2019 11:40 pm
The oxidation number refers to the charge the molecule has.