Self-test 9C.1B

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Self-test 9C.1B

Postby AnvitaaAnandkumar_1B » Wed Nov 27, 2019 11:13 am

(a) Name the compound [CoBr(NH3)5]SO4.
(b) Write the formula of tetraamminediaquachromium(III) bromide.

Ashley Nguyen 2L
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Re: Self-test 9C.1B

Postby Ashley Nguyen 2L » Wed Nov 27, 2019 11:27 am

a. The name should be pentamminebromidocobalt (III) sulfate. This is because there are 5 ammonia groups, 1 bromide atom, 1 cobalt with a +3 charge, and a sulfate.
b. The formula is [Cr(NH3)4(OH2)2] Br3

Justin Sarquiz 2F
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Re: Self-test 9C.1B

Postby Justin Sarquiz 2F » Wed Nov 27, 2019 11:31 am

The reason there are 3 Bromium atoms in part b is because Chromium has a +3 charge and Bromium has a -1 charge. Therefore, it requires 3 Bromium atoms to make the molecule neutral.

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