9C.3

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curry 1E
Posts: 55
Joined: Wed Sep 18, 2019 12:15 am

9C.3

Postby curry 1E » Mon Dec 02, 2019 1:19 pm

Could someone post the correct formulas for a-d? I want to check my answers and make sure they are exactly correct with parentheses and brackets.

Paige Lee 1A
Posts: 136
Joined: Sat Sep 07, 2019 12:16 am

Re: 9C.3

Postby Paige Lee 1A » Mon Dec 02, 2019 1:25 pm

a. K3[Cr(CN)6]
b. [Co(NH3)5SO4]Cl
c. [Co(NH3)4(OH2)2]Br3
d. Na[Fe(C2O4)2(OH2)2]

curry 1E
Posts: 55
Joined: Wed Sep 18, 2019 12:15 am

Re: 9C.3

Postby curry 1E » Mon Dec 02, 2019 1:53 pm

Why is it K3 and Br3 and not just K and Br?

Aprice_1J
Posts: 55
Joined: Wed Sep 18, 2019 12:16 am

Re: 9C.3

Postby Aprice_1J » Mon Dec 02, 2019 11:21 pm

I think the reason that it has the three is because there is no indication that the complex has a charge and so in order to neutralize it, you would have three potassium ions for the first one (you know that chromate is +3 and that cyanido is -6 so you would need +3 to get it to 0.) The same logic applies for Bromine.

Aprice_1J
Posts: 55
Joined: Wed Sep 18, 2019 12:16 am

Re: 9C.3

Postby Aprice_1J » Mon Dec 02, 2019 11:23 pm

For part d, does anyone know why diagua translates to (OH2)2? What happens between OH and H20 in the naming process?


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