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Roman numerals

Posted: Mon Dec 02, 2019 4:42 pm
by lauraxie2e
How do you know what Roman numeral to put after the name, when you're naming the compound? For example how do you know that [Fe(CN)6]4- is hexacyanidoferrate (II) and not hexacyanidoferrate (III)?

Re: Roman numerals

Posted: Mon Dec 02, 2019 4:54 pm
by Brian_Ho_2B
The sum of each oxidation number in the coordination compound should add up to the total charge of the complex, which in this case is -4. Each CN is a -1 and there's 6 of them, so those are a total of -6. To have a sum of -4, the charge of the cation must be +2.

Re: Roman numerals

Posted: Mon Dec 02, 2019 5:33 pm
by Ryan Yee 1J
The roman numeral refers to the oxidation state of the transition metal in question. In your example, Fe's charge is 2+, so you would use iron (II) when naming it. If its charge were to 3+, you would use iron (III).

Re: Roman numerals

Posted: Tue Dec 03, 2019 8:44 pm
by 105289321
The numerals represent the charge of the metal ion in question

Re: Roman numerals

Posted: Tue Dec 03, 2019 8:49 pm
by ariaterango_1A
The roman numerials represent the oxidation number of the transition metal.

Re: Roman numerals

Posted: Wed Dec 04, 2019 10:50 am
by Caroline Zepecki
You determine roman numeral by finding the oxidation number of the metal. You determine the charge on the ligand, and if the coordination compound is an ion, then you can find the oxidation number by determining what number will make all charges true.

Re: Roman numerals

Posted: Wed Dec 04, 2019 1:09 pm
by 705198479
The Roman numeral must have the same value as the charge of the ion?

Re: Roman numerals

Posted: Thu Dec 05, 2019 1:23 am
by RoshniVarmaDis1K
The roman numeral is equal to the charge on the transition metal.