Formula for tetraamminediaquacobalt(III) bromide?

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Antonio Melgoza 2K
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Joined: Fri Sep 25, 2015 3:00 am

Formula for tetraamminediaquacobalt(III) bromide?

Postby Antonio Melgoza 2K » Sat Nov 07, 2015 4:04 pm

For the formula for tetraamminediaquacobalt(III)bromide, why is bromide Br3? And why is Br3 at the end?

Christopher Ansay 1C
Posts: 28
Joined: Fri Sep 25, 2015 3:00 am

Re: Formula for tetraamminediaquacobalt(III) bromide?

Postby Christopher Ansay 1C » Sat Nov 07, 2015 4:26 pm

Br (Bromine) is the anion in this compound. We see that cobalt has a charge of +3. The four ammines and the 2 aquas are neutral. In order to create a neutral overall compound, we need to have an anion with a total charge of 3-. Bromide is a halogen and has an oxidation state of -1. Three bromide ions results in a total of 3-. Bromine is at the end because when naming coordination compounds, we put anions at the end.


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