Textbook Problem 9C.3

[905767718]

I was wondering for this question between parts a and d where the metal is written at the start of the compound compared to b and c where the nonmetal is at the end. Is there a reason for this aside from the fact that that's the way it shows up in the name? I was wondering why the nonmetals showed up at the end of the name anyways compared to the metals being at the start of the name.

[Joanna Zhao 1J]

For a and d, the metal written at the very front (K and Na respectively) is not actually part of the coordination compound. The coordination compound in general is negatively charged (anion); the K and Na (cation) metals are forming an ionic bond with the compounds. The actual compound in the brackets follows convention as we were taught it, and the entire ion in general follows the convention of cation written before anion.

Same concept but the other way around for b and c. Cl and Br aren't actually part of the coordination compound. The coordination compound is just positively charged and Cl and Br are anions.