Week 9 Q 6 Achieve

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805754009
Posts: 100
Joined: Fri Sep 24, 2021 6:06 am

Week 9 Q 6 Achieve

Postby 805754009 » Mon Nov 29, 2021 5:06 pm

On this question, we are asked to give the coordination number for the metal species. The complex at hand is [Co(en)2(CO)2]Br. Why is the coordination number for Co 6 and not 4?

Kaira Shibata 1E
Posts: 105
Joined: Fri Sep 24, 2021 5:26 am
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Re: Week 9 Q 6 Achieve

Postby Kaira Shibata 1E » Mon Nov 29, 2021 5:08 pm

en is able to bond to the Co in 2 spots as it is bidenate. With this in mind, you can see that 2 en=4 sites and 2 CO=2 sites and then 4+2=6.

Katie 3H
Posts: 113
Joined: Fri Sep 24, 2021 5:36 am

Re: Week 9 Q 6 Achieve

Postby Katie 3H » Mon Nov 29, 2021 5:14 pm

but how does 2 en end up to 4 sites?

Crystal Ma 2J
Posts: 100
Joined: Fri Sep 24, 2021 7:04 am

Re: Week 9 Q 6 Achieve

Postby Crystal Ma 2J » Mon Nov 29, 2021 5:16 pm

en is bidentate so it can bond to two spots!

Jonathan Liu 2I
Posts: 112
Joined: Fri Sep 24, 2021 6:39 am

Re: Week 9 Q 6 Achieve

Postby Jonathan Liu 2I » Mon Nov 29, 2021 5:46 pm

There are two nitrogen atom in each en molecule, which makes the molecule a bidentate, binding at two spots. This makes it have a 6 coordination number.

Iman Gauhar 3E
Posts: 104
Joined: Fri Sep 24, 2021 6:52 am

Re: Week 9 Q 6 Achieve

Postby Iman Gauhar 3E » Mon Nov 29, 2021 6:09 pm

Since the coordination number is the number of atoms, molecules, or ions bonded the the central atom, you would count 4 bonding sites from the en and 2 sites from the (CO). There are 4 bonding sites from the en because it is bidentate.


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