Homework 17.37

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Alex McCorriston Dis 3A
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Joined: Fri Sep 29, 2017 7:04 am

Homework 17.37

Postby Alex McCorriston Dis 3A » Tue Nov 21, 2017 4:53 pm

17.37 With the help of Table 17.4, determine the coordination number of the metal ion in each of the following complexes:
(a) [NiCl4]2 ; (b) [Ag(NH3)2] ; (c) [PtCl2(en)2]2 ; (d) [Cr(edta)],

I am confused about parts c and d of this question because I don't really understand what monodentate, bidentate, tridentate, etc. mean. Could somebody explain these to me? Thank you!

Jessica Lutz 2E
Posts: 56
Joined: Fri Sep 29, 2017 7:04 am

Re: Homework 17.37

Postby Jessica Lutz 2E » Tue Nov 21, 2017 6:36 pm

Bidentate means that the one ligand attaches to the central metal atom in 2 places and hexadentate means that the ligand attaches in 6 places. Each of these places that the ligand attaches to counts toward the coordination number.
For part c, that means that each ethylenediamine (en) adds 2 toward the coordination number because it is bidentate. Because there are two ethylenediamine molecules attached, its total contribution to is 4. Then there are two chlorines that are monodentate that brings the coordination number up to 6.
For part d, because edta is hexadentate and that is the only ligand in the coordination compound, the coordination number is 6.

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