Oxidation number
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Oxidation number
Can anyone explain the steps to finding the oxidation number in coordination compound? Are we going to have to know how to do this for our final?
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Re: Oxidation number
I just looked at this link and it seems to cover everything! https://socratic.org/questions/how-do-y ... a-compound
I too am curious about if we'll have to have this memorized for the final...
I too am curious about if we'll have to have this memorized for the final...
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Re: Oxidation number
The sum of oxidation numbers for a neutral compound is 0 and the sum of oxidation numbers for a polyatomic compound is the charge of the ion. By knowing specific charges for atoms (e.g. Hydrogen has a charge of +1), you can do basic algebra to solve for the charges of the other atoms.
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Re: Oxidation number
Oxidation number is the same as formal charge except bonding pairs are not split equally. They are both assigned to the more electronegative atom.
Oxidation number = V - LPE - (BE shared with less electronegative atoms)
Oxidation number = V - LPE - (BE shared with less electronegative atoms)
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Re: Oxidation number
Chem_Mod wrote:Oxidation number is the same as formal charge except bonding pairs are not split equally. They are both assigned to the more electronegative atom.
Oxidation number = V - LPE - (BE shared with less electronegative atoms)
Will we be expected to remember the charges of common polyatomic compounds for the final?
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