Homework Problem 17.33.)

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Jesus A Cuevas - 1E
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Homework Problem 17.33.)

Postby Jesus A Cuevas - 1E » Sun Jun 10, 2018 7:36 pm

Could someone help me with the following problem, thanks in advance!

Which of the following ligands can be polydentate? If the ligand can be polydentate, give the maximum number of places on the ligand that can bind simultaneously to a single metal center: (a)HN(CH2CH2NH2)2; (b)CO3 2- (c)H2O (d)Oxalate (C2O4-2)

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Re: Homework Problem 17.33.)

Postby sharonvivianv » Sun Jun 10, 2018 7:57 pm

a) tridentate, you can see that there are three nitrogens meaning there are three lone pairs.
b) bidentate, usually if there is a charge on an oxygen, a metal will be able to bind. There is a minus 2 charge.
c) monodentate, honestly I've asked around and no one has been able to give a good explanation as to why H20 is monodentate so you should just memorize that
d) bidentate, again there is a minus 2 charge.

These aren't set answers that can help you reason through every problem like this because there are always exceptions. Even the UAs have trouble telling sometimes but sometimes the charge on the oxygens and the lone pairs on the nitrogen are helpful while identifying them as polydentate.

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Re: Homework Problem 17.33.)

Postby LilianKhosravi_1H » Sun Jun 10, 2018 8:07 pm

H2O is a monodentate because even though it has two lone pairs, only one of those will bind and the other one won't because it has no way of biding to the central atom since it's on the oxygen with the other lone pair that is already bound. Basically, the positions of the lone pairs won't allow it to bind to the central atom twice.

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Re: Homework Problem 17.33.)

Postby nikitasridhar_1b » Wed Jun 13, 2018 1:05 am

what is the relation btwn charge and number of binding sites? i thought the no. of binding sites had to do wiht the number of lone pairs

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Re: Homework Problem 17.33.)

Postby Chem_Mod » Thu Jun 14, 2018 4:02 pm

Yes, number of atoms with lone pairs that can bind is what matters. Sometimes the charge may have the same value.

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