Oxidation number

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Josephine Chan 1B
Posts: 31
Joined: Fri Sep 28, 2018 12:17 am

Oxidation number

Postby Josephine Chan 1B » Fri Nov 30, 2018 9:56 pm

Hi can someone explain how to find oxidation numbers like in 17.29 (6th edition) for example? thanks

Sean Reyes 1J
Posts: 67
Joined: Fri Sep 28, 2018 12:24 am

Re: Oxidation number

Postby Sean Reyes 1J » Sat Dec 01, 2018 10:00 am

a) [Fe(CN)6]4-
Okay so for this example, if you were to look up the oxidation number of CN, you'll see that it has a -1 charge. Because there are 6, that means the charge of the iron must be +2 as the overall charge must come out to be -4. I hope that made sense.
(oxidation of Fe) + 6(-1) = -4
From this, you would solve for the oxidation of Fe, and would get +2.

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