Posted: Fri Nov 30, 2018 9:56 pm
Hi can someone explain how to find oxidation numbers like in 17.29 (6th edition) for example? thanks
Re: Oxidation number
Posted: Sat Dec 01, 2018 10:00 am
Okay so for this example, if you were to look up the oxidation number of CN, you'll see that it has a -1 charge. Because there are 6, that means the charge of the iron must be +2 as the overall charge must come out to be -4. I hope that made sense.
(oxidation of Fe) + 6(-1) = -4
From this, you would solve for the oxidation of Fe, and would get +2.