9C.3

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305303255
Posts: 40
Joined: Thu Jul 25, 2019 12:16 am

9C.3

Postby 305303255 » Tue Nov 26, 2019 12:02 pm

Can someone do part A as an example?

9C.3 Use the information in Table 9C.1 to write the formula for each of the following coordination compounds:
(a) potassium hexacyanidochromate(III)
(b) pentaamminesulfatocobalt(III) chloride
(c) tetraamminediaquacobalt(III) bromide
(d) sodium bisoxalato(diaqua)ferrate(III)

Claire Lo 3C
Posts: 55
Joined: Sat Aug 17, 2019 12:18 am

Re: 9C.3

Postby Claire Lo 3C » Tue Nov 26, 2019 12:06 pm

Since there is a space between potassium and hexacyanidochromate (III), it indicates that potassium is out of the bracket.

K3 [Cr(CN)6]

Joseph Saba
Posts: 154
Joined: Thu Jul 11, 2019 12:16 am

Re: 9C.3

Postby Joseph Saba » Tue Nov 26, 2019 12:29 pm

Always balance the charges using the outside potassium and not the chromate.

Alexa Mugol 3I
Posts: 54
Joined: Sat Aug 17, 2019 12:17 am

Re: 9C.3

Postby Alexa Mugol 3I » Tue Nov 26, 2019 2:34 pm

Claire Lo 3C wrote:Since there is a space between potassium and hexacyanidochromate (III), it indicates that potassium is out of the bracket.

K3 [Cr(CN)6]

How do you know it's K3 and not just K? Is it to neutralize the overall charge of the compound?

905416023
Posts: 54
Joined: Thu Jul 25, 2019 12:17 am

Re: 9C.3

Postby 905416023 » Tue Nov 26, 2019 2:51 pm

Claire Lo 3C wrote:Since there is a space between potassium and hexacyanidochromate (III), it indicates that potassium is out of the bracket.

K3 [Cr(CN)6]



I believe the potassium is out of the bracket not because of the space, but because it is a metal.


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